Use the equation below and determine what volume of O2 at STP is needed to react with 1.5 moles of C2H4?
Balanced equation:
C2H4 + 3O2 --> 2CO2 + 2H20
So 1 mole of C2H4/3 mol O2 --> 1.5 mols/ 4.5 mols O2. So if its 1 mol equals 1 liter, than it should be 4.5 mols of O2 x 1 liter = 4.5 Liters O2.
Is this correct or am I missing something? I am trying to work out these equations but was not given an answer key to compare to.
4.5 moles O2 is correct for that part but why did you multiply by 1 L?
1 mole O2 at STP is 22.4 L so
4.5 moles x 22.4 L = ?? volume in liters for O2.
1 mole of any ideal gas occupies 22.4 L at STP.
I'm not sure why, I think I just had a brain spasm. Some reason I always think of converting mols to liters and I had it in my head that it was a 1:1 relationship but I think its 22.4L only when it applies to a gas?
! mole of an ideal gas occupies 22.4 L at STP. 1 mole of a solid or 1 mole of a liquid depend upon dimensions and or density.
What volume of oxygen (O2) at STP is needed to react with 1.50 mol of C2H4?
What volume of oxygen (O2) at STP is needed to react with 1.50 mol of C2H4?
What is the percentage yield if 500 g of sulfur trioxide (SO3) reacts with 175 g water (H2O) to produce 575 g of sulfuric acid (H2SO4)?
To determine the volume of O2 at STP (Standard Temperature and Pressure) needed to react with 1.5 moles of C2H4, we can use the balanced equation provided:
C2H4 + 3O2 --> 2CO2 + 2H2O
Looking at the stoichiometric coefficients in the balanced equation, we see that 1 mole of C2H4 reacts with 3 moles of O2.
Given: 1.5 moles of C2H4
Using the stoichiometric coefficients, we can set up a ratio to find the number of moles of O2 needed:
1.5 moles C2H4 x (3 moles O2 / 1 mole C2H4) = 4.5 moles O2
Now, you correctly converted moles of O2 to liters using the assumption that 1 mole of an ideal gas at STP occupies 22.4 liters.
4.5 moles O2 x (1 liter O2 / 1 mole O2) = 4.5 liters O2
Therefore, your calculation of 4.5 liters of O2 is correct and it represents the volume of O2 at STP needed to react with 1.5 moles of C2H4.