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Use the equation below and determine what volume of O2 at STP is needed to react with 1.5 moles of C2H4?

Balanced equation:

C2H4 + 3O2 --> 2CO2 + 2H20

So 1 mole of C2H4/3 mol O2 --> 1.5 mols/ 4.5 mols O2. So if its 1 mol equals 1 liter, than it should be 4.5 mols of O2 x 1 liter = 4.5 Liters O2.

Is this correct or am I missing something? I am trying to work out these equations but was not given an answer key to compare to.

  • Chemistry! -

    4.5 moles O2 is correct for that part but why did you multiply by 1 L?
    1 mole O2 at STP is 22.4 L so
    4.5 moles x 22.4 L = ?? volume in liters for O2.
    1 mole of any ideal gas occupies 22.4 L at STP.

  • Chemistry! -

    I'm not sure why, I think I just had a brain spasm. Some reason I always think of converting mols to liters and I had it in my head that it was a 1:1 relationship but I think its 22.4L only when it applies to a gas?

  • Chemistry! -

    ! mole of an ideal gas occupies 22.4 L at STP. 1 mole of a solid or 1 mole of a liquid depend upon dimensions and or density.

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