arrange in order of increasing vapor pressure lowest to highest

Nacl,
ch4
ch3ch2oh

c

NaCl is a solid.

CH4 is a gas.
The last one is a liquid.
That should be enough of a hint.

^good hints

To arrange the compounds in order of increasing vapor pressure from lowest to highest, we need to consider the intermolecular forces between the molecules. The stronger the intermolecular forces, the lower the vapor pressure will be.

1. NaCl:
NaCl is an ionic compound, meaning it consists of positive and negative ions held together by strong electrostatic forces. Ionic compounds generally have low vapor pressures because they require a lot of energy to break apart the strong attractions between the ions.

2. CH4:
CH4 is a nonpolar molecule held together by weak London dispersion forces. Nonpolar molecules generally have higher vapor pressures than polar molecules because the intermolecular forces are weaker.

3. CH3CH2OH:
CH3CH2OH is a polar molecule that can form hydrogen bonds. Polar molecules generally have lower vapor pressures than nonpolar molecules due to the stronger intermolecular forces. In addition to the dipole-dipole interactions, CH3CH2OH can also form hydrogen bonds, which are even stronger.

Therefore, the arrangement of compounds in increasing vapor pressure from lowest to highest would be:
NaCl < CH4 < CH3CH2OH.

To determine the order of increasing vapor pressure from lowest to highest for NaCl, CH4, and CH3CH2OH, we need to consider the intermolecular forces present in each substance. Vapor pressure is directly influenced by the strength of these forces.

1. NaCl:
NaCl is an ionic compound composed of sodium (Na+) and chloride (Cl-) ions. It does not have any discrete molecules with intermolecular forces. Instead, it has strong ionic forces holding the ions together. As a result, NaCl does not readily evaporate, and its vapor pressure is very low. Therefore, we can place NaCl first in the order.

2. CH4:
CH4 (methane) is a nonpolar molecule composed of a carbon atom bonded to four hydrogen atoms. It possesses only London dispersion forces, which are relatively weak compared to other intermolecular forces. As a result, CH4 has a higher vapor pressure compared to NaCl. Therefore, we can place CH4 in the middle of the order.

3. CH3CH2OH:
CH3CH2OH (ethanol) is a polar molecule due to the presence of the oxygen atom. It exhibits stronger intermolecular forces such as hydrogen bonding in addition to London dispersion forces. These forces result in higher boiling points and lower vapor pressures compared to CH4. Therefore, CH3CH2OH has the highest vapor pressure among the given substances. We can place CH3CH2OH last in the order.

Therefore, the correct order from lowest to highest vapor pressure is:
NaCl < CH4 < CH3CH2OH