Post a New Question


posted by .

jet stream which is flowing at a rate of 80 miles per hour. It travels with the jet stream for 5 hours and then reduces its altitude, flying out of the jet stream for 4 more hours. The plane, while out of the jet stream, covered 550 miles less than it did during the 5 hours it was in the jet stream. How fast was the plane flying out of the jet stream?

  • trig -

    distance in stream = (v+80)5

    distance out of stream = 4 v

    4 v + 550 = 5(v+80)

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question