trig
posted by Nev .
Hi,how do I find both solutions of the equation cos0 = 0.35 between degrees 0 and 360?
Many thanks

the cosine is positive in the I and IV quadrant
using the inverse cosine function on your calculator
Ø = 69.513°
so Ø is either 69.513° or (36069.513)° or 290.487° 
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