Trigonometry

posted by .

Hi,how do I find both solutions of the equation cos41 = 0.35 between degrees 0 and 360?

Many thanks

  • Trigonometry -

    COS41 = 0.75 not 0.35. Please check your equation.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. math

    how to define arc cosine(cosine x) for -360 deg<x< 360 deg?
  2. Trigonometry

    Convert to polar coordinates with r greater than or equzl to 0 and theta between 0 degrees and 360 degrees Write the equation inpolar coordinates x squared + y squared = 2
  3. Pre-calculus

    Find the values of x in the interval 0<=x<360 that satisfy the equation x=arcsin squareroot of 2/2. Express your answer in degrees. 360 degrees - 45=315 degrees. Is this right?
  4. trig

    Hi,how do I find both solutions of the equation cos0 = 0.35 between degrees 0 and 360?
  5. trigonometry

    find all degrees solutions to the following equation: sin (A + 50 degrees)=1/square root 2
  6. trigonometry

    Find all the angles between 0 degrees and 360 degrees which satisfy the equations a. 8 cos x sin x = sin x b. 5 tan^2 y + 5 tan y = 2 sec^2 y.
  7. trigonometry

    Find all the angles between 0 degrees and 360 degrees which will satisf y the equation: 5tan^2 y +5 tan y = 2 sec^2 y
  8. Trigonometry

    Solve the equation cos^2A = sin^2A + sinA when 0¨¬¡A¡360¨¬. Select all the solutions from the list below. A. 330 degrees B. 270 degrees C. 150 degrees D. 30 degrees
  9. Trigonometry

    Find all solutions of the equation in the interval(0-360) Tan(0-30degrees)= -5
  10. Trigonometry

    Find all solutions of the equation Tan(theta - 30 degrees)= -5 in interval 0 - 360 Book gives answers for theta of 131.3 and 311.3

More Similar Questions