A 0.50-kg ball is attached to a string of 0.50 m and swung in a horizontal circle with a velocity of 1.0 m/s. What is the centripetal force of the ball?
Centripetal force = M V^2/R
1N don’t ask why
To find the centripetal force of the ball, we can use the formula:
F = (m * v^2) / r
where:
F is the centripetal force
m is the mass of the ball
v is the velocity of the ball
r is the radius of the circle
Given values:
m = 0.50 kg
v = 1.0 m/s
r = 0.50 m
Replacing the values in the formula, we get:
F = (0.50 kg * (1.0 m/s)^2) / 0.50 m
Simplifying the expression inside the brackets:
F = (0.50 kg * 1.0 m^2/s^2) / 0.50 m
F = (0.50 kg * 1.0 m/s^2)
F = 0.50 kg * 1.0 m/s^2
F = 0.50 Newtons
Therefore, the centripetal force of the ball is 0.50 Newtons.
To find the centripetal force of the ball, you need to use the formula:
F = (m * v^2) / r
where:
F is the centripetal force,
m is the mass of the ball,
v is the velocity of the ball, and
r is the radius of the circle.
In this case, the mass of the ball is given as 0.50 kg, the velocity is given as 1.0 m/s, and the radius is given as 0.50 m.
Plugging in the values into the formula, we get:
F = (0.50 kg * (1.0 m/s)^2) / 0.50 m
Simplifying the formula:
F = (0.50 kg * 1.0 m^2/s^2) / 0.50 m
F = (0.50 kg * 1.0) / 0.50
F = 1.0 N
Therefore, the centripetal force of the ball is 1.0 N.