posted by Cindy .
3.The solubility product for silver (I) chloride is 1.6x10^-10 while that for sliver (I) iodide is 8.5x10^-17. Suppose 5g of AgCl is put in a liter of 0.1M sodium iodide solution. If a solid is eventually isolated, what is it, and how did it form?
This is a good thinking question but there are so many variables that are not listed. Which solid is more soluble? So which should predominate IF GIVEN ENOUGH TIME.
AgCl is insoluble / dissolves really slowly, but I'm guessing from the question that it means the latter. It should form AgI given enough time.