When magnesium is heated in air, it reacts with oxygen to form magnesium oxide.

2Mg + O2 --> 2MgO
If the mass of the magnesium increases by 0.335 g, how many grams of magnesium reacted?
A. 0.882
B. 0.441
C. 0.509
D. 1.02
E. Not enough Info

Thanks I got it now

zinc plus copper sulfate gives zinc sulfate plus copper

Sugbkvgjb

To determine the mass of magnesium that reacted, we need to calculate the difference between the initial and final masses.

Let's assume the initial mass of the magnesium is "x" grams. According to the equation, 2 moles of magnesium react with 1 mole of oxygen to form 2 moles of magnesium oxide.

From the equation, we can see that the molar ratio between magnesium and magnesium oxide is 2:2, which simplifies to 1:1. This means that the mass ratio is also 1:1.

Based on this, the increase in mass of magnesium (0.335 g) is equal to the mass of magnesium oxide formed. Therefore, the mass of magnesium that reacted is also 0.335 g.

Therefore, the answer is B. 0.441 grams of magnesium reacted.

The added mass of 0.335 g must be due to the added oxygen. I would convert 0.335 g O2 to moles, use the coefficients in the balanced equation to convert to moles Mg and multiply by moles mass to convert to grams Mg. Post your work if you get stuck.