alg

posted by sean

solve: 1 / x + 2 + 1 / x - 2= 1 / x^2 - 4

a)-2
b) 2
c)-1/2
d) 1/2

  1. Reiny

    you probably meant to type
    1/(x + 2) + 1/(x - 2) = 1/(x^2 - 4)

    multiply each term by x^2 - 4, ( which factors to (x+2)(x-2) )

    x-2 + x+2 = 1
    2x = 1
    x = 1/2

  2. bobpursley

    multiply both sides by (x+2)(x-2)

    x-2+x+2=1
    x= 1/2

  3. sean

    thanks reiny

Respond to this Question

First Name

Your Answer

Similar Questions

  1. alg

    Solve: 2 / x - 1 - 3/4 = 5 / x - 1 a) -2 b) 2 c) 3 d) -3
  2. alg

    solve: 2 / x - 1 - 3/4 = 5 / x - 1 a) -3 b) 3 c) 2 d) -2
  3. Alg. 2

    3x-2/12 - 1/6 = 1/6 Please help me to solve.
  4. Alg

    solve: x + 8 = 2(x-2) - x
  5. math ALG 2!

    -|8X-3Y|+|2Y+5X|.....SOLVE
  6. math ALG 2!

    7F-9>3F-1 SOLVE
  7. simple alg 2!!!

    a=-2 b=3 |a+b|? solve
  8. Alg 1

    Solve the proportion: 4/x = (radical sign over 11, not -1) 11 - 1/3 Please solve and explain. My answer does not match any of my choices.
  9. alg 2

    solve the inequality y<|x+8|-4
  10. math i need help

    What is the simplified form of each expression?

More Similar Questions