posted by Ana .
I have a 45-45 special right triangle who's hypotenuse is 12, how do I find the other two side lengths?
Since the 2 angles are equal, the 2 sides are also equal.We'll call the
horizontal side X and the vertical side Y. X=12*Cos45=8.48, Y=12*Sin45=8.48. NOTE: the sin45=Cos45.
Since they are of equal length, let a = length of each side.
Pythagorean theorem = a^2 + a^2 = hypotenuse^2
Therefore 2a^2 = 12^2
Can you take it from there?