posted by love .
Assuming the density of a 5% acetic acid solution is 1.0 g/mL, determine the volume of the acetic acid solution necessary to neutralize 25.0 mL of 0.10 M NaOH. Record this calculation on your report sheet.
5% acetic acid means 5 g/100 g soln.
How many moles NaOH will you need to neutralize. M x L = ??
You will need that many moles of aceitic acid. Convert 5% acetic acid to molarity.
5g/100 g. Convert 100 g soln to volume using the density. Convert 5 g acetic acid to moles. moles = grams/molar mass.
Post your work if you get stuck.