posted by josh
A 1210 N uniform beam is attached to a vertical wall at one end and is supported by a cable at the other end. A W = 1820 N crate hangs from the far end of the beam. The angle between the beam and the horizontal is 30 degrees upwards and the angle between the horizontal and the cable attached to the wall is 50 degrees upward.
Calculate the magnitude of the tension in the wire.
Beam length a
t = tension in cable
moments clockwise at wall hinge
1210(a/2)cos 30 + 1820 a cos 30 - t a sin 50 cos 30 = 0 (note a cancels, is irrelevant)
524 + 1576 =.663 t
solve this for t