85.0 grams of potassium bromide are to be used to produce a 0.300M solution. What will be the total volume of this solution?
To find the total volume of the solution, you can use the formula:
Molarity = moles/volume
First, we need to determine the number of moles of potassium bromide using its molar mass. The molar mass of potassium bromide (KBr) is:
K (39.1 g/mol) + Br (79.9 g/mol) = 119 g/mol
So, the number of moles can be calculated as:
moles = mass / molar mass
moles = 85.0 g / 119 g/mol
moles = 0.714 mol
Now, we can rearrange the formula to find the volume:
volume = moles / Molarity
volume = 0.714 mol / 0.300 M
volume ≈ 2.38 L
Therefore, the total volume of the 0.300M solution of potassium bromide will be approximately 2.38 liters.
To find the total volume of the solution, you need to use the formula:
Molarity (M) = moles of solute / volume of solution (L)
First, you need to calculate the moles of potassium bromide (KBr) using the given mass and the molar mass of KBr.
The molar mass of KBr is calculated by adding the atomic masses of potassium (K) and bromine (Br):
K = 39.10 g/mol
Br = 79.90 g/mol
Molar mass of KBr = 39.10 g/mol + 79.90 g/mol = 119.00 g/mol
Next, use the formula:
moles of solute = mass of solute / molar mass of solute
moles of KBr = 85.0 g / 119.00 g/mol
Now, substitute the values into the first equation to solve for the volume of solution:
0.300 M = (85.0 g / 119.00 g/mol) / volume of solution (L)
Rearrange the equation to solve for the volume of solution:
volume of solution (L) = (85.0 g / 119.00 g/mol) / 0.300 M
Perform the calculations:
volume of solution (L) = 0.713 L
Therefore, the total volume of the 0.300 M potassium bromide solution will be 0.713 liters (L).
85.0 g/molar mass KBr = moles KBr.
M = moles/L of soln.
You know M and moles, calculate L of soln.
Post your work if you get stuck.