. Suppose a certain species of fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean kilograms and standard deviation kilograms. Let x be the weight of a fawn in kilograms. Convert the following x interval to a z interval. Round to the nearest hundredth.
x < 19.2
You do not give the mean or SD.
Z = (x - μ)/SD
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion below that Z score.
-2.23
To convert the x interval to a z interval, we need to use the formula for z-score:
z = (x - mean) / standard deviation
First, we need to find the z-score for the lower bound of the x interval. In this case, x < 19.2 is our lower bound. Let's assume the mean of the fawn weights is μ kilograms, and the standard deviation is σ kilograms. The lower bound is 19.2 kilograms.
z = (19.2 - μ) / σ
Next, we need to round the z-score to the nearest hundredth.