maths - trigonometry

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I have my maths exam on Tuesday and cannot remember how to do trigonometric identities at all. I was so sure, but now I'm not. I asked a similar question earlier, but I still don't quite understand. Please give me step-by-step instructions?

[sinx + tanx] / [cosx +1] = tanx

  • maths - trigonometry -

    I just got done with thi stuff and these are the formulas that helped me with alot.
    tan(angle)=opposite/adjacent

    coa(angle)=adjacent/hypotenuse

    sin(angle)=opposite/hypotenuse

    Is this what your asking for?

  • maths - trigonometry -

    that's sort of a tricky one,

    [sinx + tanx] / [cosx +1] = tanx
    LS = (sinx + tanx)/(cosx+1) [(cosx-1)/cosx-1)]
    = (sinxcosx - sinx + sinx - sinx/cosx)/(cos^2x - 1)
    = [ (sinxcos^2x - sinx)/cosx]/(cos^2x - 1)
    = sinx[cos^2x - 1)/cosx] / (cos^2x - 1)
    = sinx/cosx
    = tanx
    = RS

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