posted by Kellsey .
Consider the following equilibrium:
CoCl42-(ac) + 6 H2O (l) = Co(H2O)62+ (ac) + 4 Cl-
what effect will adding NaOH have on the equilibrium and on K constant.
the chemical reaction is the following:
(CoCl4)^2- (ac) + 6 H2O (l) = ( Co(H2O)6)^2 + (ac) + 4 Cl-
sorry it's not that understandable in the first post.