8+2+1/2+...(find the first 11 terms)
looks geometric with
a=8
r=1/4
sum(11) = a(1-r^11)/(1-r)
= 8(1-(1/4)^11)/(1-1/4)
I will let you work it out
a=8
r=1/4
sum(11) = a(1-r^11)/(1-r)
= 8(1-(1/4)^11)/(1-1/4)
I will let you work it out