A volume of 35.0 mL of nitrogen gas was collected over water at 24 degrees C and 99.1kPa. The vapor pressure of water at this temperature is 2.99 kPa.

What is the pressure of the nitrogen gas alone?

96.11 kPa

Dalton's Law of Partial Pressures says that the total pressure of the gases in a vessel is the sum of the individual partial pressures. Therefore,

Ptotal = PN2 + PH2O.

Well, I have to say, trying to measure gas pressure over water sounds like a real "pressure cooker" situation! But don't worry, I'm here to help you out, even if my jokes might be a bit "deflated."

To find the pressure of the nitrogen gas alone, you'll need to subtract the vapor pressure of water from the total pressure. So, here's the calculation:

Total pressure = Pressure of nitrogen gas + Vapor pressure of water

99.1 kPa = Pressure of nitrogen gas + 2.99 kPa

Now it's time to do some "pressure-puzzling" math:

Pressure of nitrogen gas = 99.1 kPa - 2.99 kPa

That gives us:

Pressure of nitrogen gas = 96.11 kPa

So, the pressure of the nitrogen gas alone is 96.11 kPa. And just remember, when dealing with pressure, it's always important to "stay cool" and avoid getting all "pressurized" about the calculations!

To find the pressure of the nitrogen gas alone, we need to subtract the vapor pressure of water from the total pressure.

Here's how you can calculate it:

1. Convert all pressure values to the same units. In this case, we'll use kilopascals (kPa) for simplicity.
- Total pressure: 99.1 kPa
- Vapor pressure of water: 2.99 kPa

2. Subtract the vapor pressure of water from the total pressure:
- Pressure of the nitrogen gas alone = Total pressure - Vapor pressure of water
- Pressure of the nitrogen gas alone = 99.1 kPa - 2.99 kPa

3. Calculate the result:
- Pressure of the nitrogen gas alone = 96.11 kPa

Therefore, the pressure of the nitrogen gas alone is 96.11 kPa.

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