I need to find how many grams phosphorus (P) are in 0.8645 g sample of MgNH4PO4 x 6H2O
How many grams P2O5 can be calculated with this many grams of P
What is the percent P (as P2O5) in this
moles MgNH4PO4.6H2O in 0.8645 g MgNH4PO4.6H2O =
0.8645/molar mass MgNH4PO4.6H2O = ?? moles.
Then ?? moles x (1 mole P/1 mole MgNH4PO4.6H2O = ?? moles x 1/1 = xx moles P.
Then g P = moles P x molar mass P.
To find the number of grams of phosphorus (P) in the sample, we can start by calculating the molar mass of the compound MgNH4PO4 x 6H2O.
The molar mass of MgNH4PO4 x 6H2O can be calculated as follows:
Molar mass of MgNH4PO4 = (24.31 g/mol) + (14.01 g/mol) + 4((1.01 g/mol) + (14.01 g/mol) + (16.00 g/mol)) + (15.99 g/mol) + 4(2.02 g/mol) + 6(1.01 g/mol)
= 120.34 g/mol
Since the formula unit of MgNH4PO4 contains 1 atom of phosphorus, the number of grams of P in the sample is given by:
Number of grams of P = (0.8645 g) x (1 mol / 120.34 g) x (1 mol P / 1 mol MgNH4PO4) x (30.97 g / 1 mol P)
= 0.2161 g
Now, to calculate how many grams of P2O5 can be obtained from this amount of P, we need to consider the molar mass of P2O5.
Molar mass of P2O5 = (2 x 30.97 g/mol) + (5 x 16.00 g/mol)
= 141.94 g/mol
The number of grams of P2O5 can be calculated as:
Number of grams of P2O5 = (0.2161 g) x (1 mol / 30.97 g) x (1 mol P2O5 / 1 mol P) x (141.94 g / 1 mol P2O5)
= 0.9894 g
Finally, to determine the percent P (as P2O5) in the compound, we need to consider the total mass of the compound.
Total mass of MgNH4PO4 x 6H2O = (0.8645 g) + (6 x 18.02 g/mol) + (0.2161 g)
= 1.2979 g
The percent P (as P2O5) is given by:
Percent P (as P2O5) = (0.9894 g / 1.2979 g) x 100%
= 76.21%
To find the number of grams of phosphorus (P) in the given sample of MgNH4PO4 x 6H2O, you need to use the molar mass of MgNH4PO4 x 6H2O and the molar mass of phosphorus (P).
1. Find the molar mass of MgNH4PO4 x 6H2O:
- Mg: 1 atom x 24.31 g/mol = 24.31 g/mol
- N: 1 atom x 14.01 g/mol = 14.01 g/mol
- H: 12 atoms x 1.01 g/mol = 12.12 g/mol
- P: 1 atom x 31.00 g/mol = 31.00 g/mol
- O: 10 atoms x 16.00 g/mol = 160.00 g/mol
- H2O: 6 molecules x 18.02 g/mol = 108.12 g/mol (6 water molecules)
Adding up all the masses: 24.31 + 14.01 + 12.12 + 31.00 + 160.00 + 108.12 = 349.56 g/mol
2. Calculate the moles of MgNH4PO4 x 6H2O:
Given mass: 0.8645 g
Moles = Mass / Molar mass
Moles = 0.8645 g / 349.56 g/mol = 0.002469 mol
3. Calculate the moles of phosphorus (P):
Since there is 1 mole of P in 1 mole of MgNH4PO4 x 6H2O, the moles of P is also 0.002469 mol.
4. Convert moles of P to grams:
Molar mass of P = 31.00 g/mol
Grams = Moles x Molar mass
Grams = 0.002469 mol x 31.00 g/mol = 0.076539 g
Therefore, there are approximately 0.076539 grams of phosphorus (P) in the 0.8645 g sample of MgNH4PO4 x 6H2O.
To calculate the grams of P2O5 using this many grams of P (0.076539 g), you need to use the molar mass of P2O5:
1. Find the molar mass of P2O5:
- P: 2 atoms x 31.00 g/mol = 62.00 g/mol
- O: 5 atoms x 16.00 g/mol = 80.00 g/mol
Adding up all the masses: 62.00 + 80.00 = 142.00 g/mol
2. Calculate the moles of P2O5:
Moles = Grams / Molar mass
Moles = 0.076539 g / 142.00 g/mol = 0.000539 mol
3. Convert moles of P2O5 to grams:
Grams = Moles x Molar mass
Grams = 0.000539 mol x 142.00 g/mol = 0.076558 g
Therefore, you can calculate approximately 0.076558 grams of P2O5 from 0.076539 grams of phosphorus (P).
To find the percent P (as P2O5) in this sample, you need to use the molar mass of P2O5 and the calculated grams of P2O5 and P:
1. Find the molar mass of P2O5:
P2O5 has a molar mass of 142.00 g/mol (calculated earlier).
2. Calculate the percent P (as P2O5):
Percent P = (Mass of P2O5 / Total mass of MgNH4PO4 x 6H2O) x 100
Percent P = (0.076558 g / 0.8645 g) x 100 ≈ 8.866%
Therefore, the percent P (as P2O5) in the given sample is approximately 8.866%.