Calculate the theoretical yield of barium sulfate using your assigned volume. I was assigned 30mL of BaCl2. The balanced equation is: H2SO4 + BaCl2 -> 2HCl + BaSO4. In the experiment we used .20M BaCl2, .60M H2SO4 and 1M HCL
moles BaCl2 = M x L.
Using the coefficients in the balanced equation, convert moles BaCl2 to moles BaSO4.
Convert moles BaSO4 to grams. g = moles x molar mass. This is the theoretical yield.
To calculate the theoretical yield of barium sulfate, we need to follow these steps:
Step 1: Convert the given volume of BaCl2 to moles.
We are given 30 mL of BaCl2. Since we are provided with the concentration of BaCl2, we can convert the volume to moles using the formula:
moles = concentration (M) × volume (L)
First, we need to convert the given volume from milliliters (mL) to liters (L):
30 mL = 30 ÷ 1000 = 0.03 L
Now we can calculate the moles of BaCl2:
moles of BaCl2 = 0.20 M × 0.03 L = 0.006 mol
Step 2: Determine the stoichiometric ratio between BaCl2 and BaSO4.
From the balanced equation, we can see that the stoichiometric ratio between BaCl2 and BaSO4 is 1:1. This means that for every 1 mole of BaCl2, we should obtain 1 mole of BaSO4.
Step 3: Calculate the moles of BaSO4.
Since the stoichiometric ratio between BaCl2 and BaSO4 is 1:1, the moles of BaSO4 will be the same as the moles of BaCl2.
moles of BaSO4 = 0.006 mol
Step 4: Convert moles of BaSO4 to grams.
To convert moles of BaSO4 to grams, we need to use the molar mass of BaSO4. The molar mass of BaSO4 is calculated by adding the atomic masses of each element:
Ba: 137.33 g/mol
S: 32.07 g/mol
O4: (16.00 g/mol) × 4 = 64.00 g/mol
Molar mass of BaSO4 = 137.33 g/mol + 32.07 g/mol + 64.00 g/mol = 233.40 g/mol
Now we can calculate the theoretical yield of BaSO4:
Theoretical yield of BaSO4 = moles of BaSO4 × molar mass of BaSO4
Theoretical yield of BaSO4 = 0.006 mol × 233.40 g/mol
Theoretical yield of BaSO4 = 1.40 g
Therefore, the theoretical yield of barium sulfate using the given volume of 30 mL of BaCl2 is 1.40 grams.