find z such that 5.2% of the standard normal curve lies to the left of z
You have to do a reverse lookup on a standard distribution table to find the answers.
Or, if you have excel, use the NORMSINV function.
1. P(X≤z) = 0.052
z = -1.626
in Excel, the cell for your result has the formula =NORMSINV(0.052). easy. Or you can find your favorite z-table and find out. If your z-value table only has the values for z≥0, just find the value of z for P(X≤z) = 0.948, and you'll have -z.
Sure, let's find that hilarious z value!
To find z such that 5.2% of the standard normal curve lies to the left of it, we just need to consult the Clown-O-Meter! *boop boop*
*Clown-O-Meter activates*
*Beeping and honking sounds*
**BZZZT!**
Ok, I got it! The hilarious z value we're looking for is -1.681!
So, if you see a clown with a nose that's -1.681 standard deviations long, you know it's the one we're talking about! Enjoy the circus!
To find the value of z such that 5.2% of the standard normal curve lies to the left of it, we need to use a standard normal distribution table or a statistical calculator. The standard normal distribution table provides the proportion of area under the curve to the left of each z-score.
Here's how we can find the value of z:
1. Start by drawing a standard normal distribution curve.
2. Identify the area to the left of z, which is 5.2% in this case.
3. The standard normal table provides z-scores for cumulative probabilities (areas) to the left of z. However, since we are given the area to the left of z, we need to find the corresponding z-score.
4. Look for the closest value to 5.2% in the table. The exact value might not be available, so find the closest values below and above 5.2% in the table. Let's say we find that the closest values are 5.16% and 5.26%.
5. Identify the z-scores corresponding to the closest values from the table. Let's say the z-scores are -1.68 and -1.67.
6. Determine which z-score is closer to 5.2%. In this case, 5.16% is closer to 5.2% than 5.26% so we use the z-score of -1.68.
7. Therefore, z ≈ -1.68.
Using this method, we can determine the value of z such that 5.2% of the standard normal curve lies to the left of it to be approximately -1.68.