Is this correct?
Evaluate the exponential equation for three positive values of x, three negative values of x, and at x=0. Show your work. Use the resulting ordered pairs to plot the graph;
y=(1/4)^x+3
x = -1, y = 7
x = -0.5, y = 5
x = 0, y = 4
x = 0.5, y = 3.5
x = 1, y = 3.25
x = 1.5, y = 3.125
Graphing: x = -1/5, y = 11
No Vertical Asymptotes
Horizontal Asymptote y=3
They are all correct except
when x = -1.5, I get y = 4.3195
Are you the same person who posted this ....
http://www.jiskha.com/display.cgi?id=1276428538
They are all correct except
when x = -1/5, I get y = 4.3195
Are you the same person who posted this ....
http://www.jiskha.com/display.cgi?id=1276428538
To evaluate the exponential equation for three positive values of x, three negative values of x, and at x=0, you need to substitute these values into the equation and compute the corresponding y values.
Let's start with the positive values of x:
1. For x = 0.5:
y = (1/4)^(0.5) + 3
y = 1/2 + 3
y = 3.5
So, the ordered pair is (0.5, 3.5).
2. For x = 1:
y = (1/4)^1 + 3
y = 1/4 + 3
y = 3.25
The ordered pair is (1, 3.25).
3. For x = 1.5:
y = (1/4)^1.5 + 3
y = 1/8 + 3
y = 3.125
The ordered pair is (1.5, 3.125).
Now, let's evaluate the equation for the negative values of x:
1. For x = -1:
y = (1/4)^(-1) + 3
y = 4 + 3
y = 7
The ordered pair is (-1, 7).
2. For x = -0.5:
y = (1/4)^(-0.5) + 3
y = 2 + 3
y = 5
The ordered pair is (-0.5, 5).
3. For x = -1.5:
y = (1/4)^(-1.5) + 3
y = 8 + 3
y = 11
The ordered pair is (-1.5, 11).
Finally, substituting x = 0:
y = (1/4)^0 + 3
y = 1 + 3
y = 4
The ordered pair is (0, 4).
Using these ordered pairs, you can now plot the graph. The x-axis will represent the values of x, and the y-axis will represent the values of y. Connect all the points, and you will have the graph of the exponential equation.
The graph has no vertical asymptotes, meaning there are no values of x that cause the equation to be undefined. It has a horizontal asymptote at y=3, which means that as x approaches positive or negative infinity, the value of y approaches 3.