How many liters of O2 can be produced by letting 12.00 moles of KClO3 react?
2KClO3 ==> 2KCl + 3O2
12.00 moles KClO3 x (3 moles O2/2 moles KClO3) - 12.00 x (3/2) = ??
To find out how many liters of O2 can be produced, we need to use the given information about the number of moles of KClO3 and apply the balanced chemical equation of the reaction.
The balanced chemical equation for the reaction of KClO3 decomposing into KCl and O2 is:
2 KClO3 → 2 KCl + 3 O2
From the equation, we can see that 2 moles of KClO3 will produce 3 moles of O2. Therefore, to find the number of moles of O2 produced, we need to calculate the moles of O2 using a mole-to-mole ratio.
Given:
Moles of KClO3 = 12.00 moles
To calculate the moles of O2, we can use the mole ratio between KClO3 and O2:
Moles of O2 = (12.00 moles KClO3) x (3 moles O2 / 2 moles KClO3)
Moles of O2 = 18.00 moles
Now that we have the number of moles of O2, we can convert it to liters using the ideal gas law.
The ideal gas law, PV = nRT, relates the volume (V), pressure (P), number of moles (n), and temperature (T) of a gas.
Assuming the temperature and pressure are constant, we can rearrange the ideal gas law to solve for volume:
V = (nRT) / P
Given:
Pressure (P) = You haven't provided any information about the pressure.
Temperature (T) = You haven't provided any information about the temperature.
Without knowing the pressure and temperature, we cannot calculate the volume of O2 in liters.