Find the center and radius of the circle with the equation (x - 2)2 + y2 = 5.
a.)(2,0), √5
b.)(-2,0), 5
c.)(-2,0), √5
The center of the circular graph of
(x-2)^2 + y^2 = 5
is at (x=2,y=0), and the radius is sqrt5.
Please use ^ before exponents.
Thanks and I will make sure i use ^ before exponents:)
To find the center and radius of a circle with an equation in the form (x - h)^2 + (y - k)^2 = r^2, we can compare it with the standard form of a circle equation which is (x - a)^2 + (y - b)^2 = r^2.
In the given equation, (x - 2)^2 + y^2 = 5, we can identify that h = 2, k = 0, and r^2 = 5.
So, the center of the circle is (h, k), which is (2, 0), and the radius of the circle is equal to the square root of r^2, which is √5.
Therefore, the correct answer is option a.)(2,0), √5.