the force exerted on a rope pulling a wagon is 49 N. the rope is 35 degrees above the horizontal. find the force that pulls the wagon over the ground.
That would be 49 cos35 Newtons
It equals 40.1 N
To find the force that pulls the wagon over the ground, we need to break down the force exerted on the rope into its horizontal and vertical components.
First, let's find the vertical component of the force (Fv). It can be calculated using the equation:
Fv = F * sin(θ)
where F is the force exerted on the rope (49 N) and θ is the angle the rope makes with the horizontal (35 degrees).
Fv = 49 N * sin(35 degrees)
Now, let's calculate the horizontal component of the force (Fh). It can be calculated using the equation:
Fh = F * cos(θ)
Fh = 49 N * cos(35 degrees)
Now, we have the vertical component (Fv) and horizontal component (Fh) of the force. The force that pulls the wagon over the ground is equal to the horizontal component because gravity only acts vertically.
Therefore, the force that pulls the wagon over the ground is approximately equal to 49 N * cos(35 degrees).