Find the vertex of the parabola. y=x^2-6x+7

To find the vertex of a parabola in the form of y = ax^2 + bx + c, you can use the formula x = -b/2a and substitute it back into the equation to find the y-coordinate.

In the given equation, y = x^2 - 6x + 7, we can see that a = 1, b = -6, and c = 7.

First, let's find the x-coordinate of the vertex using the formula: x = -b/2a.

Plugging in the values, we have:
x = -(-6)/(2*1)
x = 6/2
x = 3

Now, substitute the x-coordinate back into the equation to find the y-coordinate:
y = (3)^2 - 6(3) + 7
y = 9 - 18 + 7
y = -2

Therefore, the vertex of the parabola y = x^2 - 6x + 7 is (3, -2).