Calculate the mass defect and the binding energy/nucleon of the nuclide 9/4 Be which has a mass of 9.012 182 24 amu. The mass of a proton is 1.007 276 47 amu and the mass of a neutron is 1.008 664 90. one amu= 1.6605*10^-27 and the speed of light is 3.00*10^8 m/s

My goodness, Michael, Kelly, Christina -- or whatever you name is -- you just posted 8 chemistry questions. Do you know how to start any of them?

Hi sorry - We have been working together trying to figure them out. and no we don't know

Add mass electrons, mass neutrons, mass protons to find sum, subtract from the mass of the atom to find the mass defect. Delta E = delta m*c2

Delta E/number of nucleons = energy/nucleon.

To calculate the mass defect and binding energy/nucleon of a nuclide, we need to first determine the total mass of the nuclide and then subtract the mass of the individual protons and neutrons.

1. Convert the masses of the proton, neutron, and the nuclide from atomic mass units (amu) to kilograms (kg).
- Mass of the proton (mp) = 1.007 276 47 amu * (1.6605 × 10^-27 kg / 1 amu)
- Mass of the neutron (mn) = 1.008 664 90 amu * (1.6605 × 10^-27 kg / 1 amu)
- Mass of the nuclide (m) = 9.012 182 24 amu * (1.6605 × 10^-27 kg / 1 amu)

2. Calculate the total mass of the nuclide by summing the masses of the protons and neutrons.
- Total mass of the nuclide (M) = (9 * mp) + (4 * mn)

3. Calculate the mass defect (Δm) by subtracting the total mass of the nuclide from the mass of the nuclide.
- Mass defect (Δm) = m - M

4. Convert the mass defect from kilograms to atomic mass units by dividing by the conversion factor.
- Mass defect (Δm) in amu = Δm / (1.6605 × 10^-27 kg / 1 amu)

5. Calculate the binding energy/nucleon (BE/A) by dividing the binding energy (BE) by the number of nucleons (A).
- Binding energy (BE) = ΔE * c^2, where c is the speed of light (3.00 × 10^8 m/s)
- Number of nucleons (A) = 9 (number of protons + number of neutrons)
- Binding energy/nucleon (BE/A) = BE / A

Let's put these calculations into practice:

1. mp = 1.007 276 47 amu * 1.6605 × 10^-27 kg / 1 amu ≈ 1.67262192 × 10^-27 kg
mn = 1.008 664 90 amu * 1.6605 × 10^-27 kg / 1 amu ≈ 1.67492374 × 10^-27 kg
m = 9.012 182 24 amu * 1.6605 × 10^-27 kg / 1 amu ≈ 1.49625307 × 10^-26 kg

2. M = (9 * 1.67262192 × 10^-27 kg) + (4 * 1.67492374 × 10^-27 kg) ≈ 1.50384154 × 10^-26 kg

3. Δm = 1.49625307 × 10^-26 kg - 1.50384154 × 10^-26 kg ≈ -7.588 × 10^-29 kg

4. Mass defect (Δm) in amu = -7.588 × 10^-29 kg / (1.6605 × 10^-27 kg / 1 amu) ≈ -0.4575 amu

5. BE = Δm * c^2 = -7.588 × 10^-29 kg * (3.00 × 10^8 m/s)^2 ≈ -6.83 × 10^-12 J
A = 9 (number of protons + number of neutrons)
BE/A = (-6.83 × 10^-12 J) / 9 ≈ -7.59 × 10^-13 J/nucleon

Therefore, the mass defect of the nuclide 9/4 Be is approximately -0.4575 amu, and the binding energy/nucleon is approximately -7.59 × 10^-13 J/nucleon.