Calculate the mass defect and the binding energy/nucleon of the nuclide 9/4 Be which has a mass of 9.012 182 24 amu. The mass of a proton is 1.007 276 47 amu and the mass of a neutron is 1.008 664 90. one amu= 1.6605*10^-27 and the speed of light is 3.00*10^8 m/s
see above.
To calculate the mass defect and binding energy/nucleon of a nuclide, we need to use the equation:
Binding energy = (Mass of the nuclide - Sum of the masses of its protons and neutrons) * (mass unit * speed of light^2)
First, let's calculate the sum of the masses of protons and neutrons:
Number of protons = 4 (according to the nuclide 9/4 Be)
Number of neutrons = 9 - 4 = 5
Mass of protons = Number of protons * Mass of a proton = 4 * 1.00727647 amu
Mass of neutrons = Number of neutrons * Mass of a neutron = 5 * 1.00866490 amu
Now, let's calculate the mass defect:
Mass defect = Mass of the nuclide - (Mass of protons + Mass of neutrons)
Mass defect = 9.01218224 amu - (4 * 1.00727647 amu + 5 * 1.00866490 amu)
Next, we need to convert the mass defect from amu to kilograms:
1 amu = 1.6605 × 10^-27 kg
Mass defect (in kg) = Mass defect (in amu) * (1.6605 × 10^-27 kg/amu)
Finally, let's calculate the binding energy/nucleon:
Binding energy/nucleon = Mass defect * (mass unit * speed of light^2) / (Number of protons + Number of neutrons)
Binding energy/nucleon = Mass defect (in kg) * (1 amu/1.6605 × 10^-27 kg) * (speed of light^2)
Now, we can substitute the values and calculate the mass defect and binding energy/nucleon for nuclide 9/4 Be.