college physics

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A small mass M and a small mass 3M are 1.00 m apart. Where should you put a third small mass so that the net gravitational force on it due to the other two masses is zero?

  • college physics -

    do it this way
    M(x)=3M(100-x)
    x=300-3x
    4x=300
    x=75cm
    or 0.75m

  • college physics -

    Gravitational force
    =GMm/r²

    So for the mass m between masses M and 3M, one metre apart, equate the gravitational forces:
    GMm/x² = G(3M)m/(1-x)²
    Solve for x.
    [(√3-1)/2]

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