15. What volume of NH3 at STP is produced if 25.0g of N2 is reacted with an excess of hydrogen gas? N2 + 3H2 →2NH3
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To determine the volume of NH3 produced at STP, you need to follow these steps:
Step 1: Convert the given mass of N2 to moles using its molar mass.
The molar mass of N2 is 28.02 g/mol.
Number of moles of N2 = Mass of N2 / Molar mass of N2
Number of moles of N2 = 25.0 g / 28.02 g/mol
Step 2: Determine the stoichiometry of the reaction to find the mole ratio between N2 and NH3.
From the balanced equation, the mole ratio between N2 and NH3 is 1:2.
Step 3: Use the mole ratio to find the moles of NH3 formed.
Number of moles of NH3 = Number of moles of N2 x (2 moles of NH3 / 1 mole of N2)
Step 4: Convert moles of NH3 to volume at STP using the ideal gas law.
At STP (Standard Temperature and Pressure), 1 mole of any ideal gas occupies 22.4 liters.
Volume of NH3 at STP = Number of moles of NH3 x 22.4 L/mol
Now, let's calculate the volume of NH3 produced at STP:
Number of moles of N2 = 25.0 g / 28.02 g/mol = 0.892 mol
Number of moles of NH3 = 0.892 mol x (2 mol NH3 / 1 mol N2) = 1.784 mol
Volume of NH3 at STP = 1.784 mol x 22.4 L/mol ≈ 39.93 L
Therefore, approximately 39.93 liters of NH3 will be produced at STP.
To determine the volume of NH3 produced, we first need to use the given information to calculate the number of moles of N2.
Step 1: Calculate the number of moles of N2.
We can use the molar mass of N2 to convert grams of N2 to moles of N2.
The molar mass of N2 is approximately 28.01 g/mol.
So, the number of moles of N2 can be calculated as follows:
moles of N2 = mass of N2 / molar mass of N2
moles of N2 = 25.0 g / 28.01 g/mol
moles of N2 ≈ 0.892 mol
Step 2: Use stoichiometry to determine the moles of NH3 produced.
From the balanced equation N2 + 3H2 → 2NH3, we can see that for every 1 mole of N2, 2 moles of NH3 are produced.
Therefore, the moles of NH3 can be calculated as follows:
moles of NH3 = 2 * moles of N2
moles of NH3 ≈ 2 * 0.892 mol
moles of NH3 ≈ 1.784 mol
Step 3: Use ideal gas law to find the volume of NH3 at STP.
At standard temperature and pressure (STP), 1 mole of any ideal gas occupies 22.4 liters.
So, the volume of NH3 can be calculated as follows:
volume of NH3 = moles of NH3 * 22.4 L/mol
volume of NH3 ≈ 1.784 mol * 22.4 L/mol
volume of NH3 ≈ 39.9424 L
Therefore, the volume of NH3 at STP produced from the reaction of 25.0 g of N2 is approximately 39.9424 liters.
Convert 25.9 g N2 to moles. moles = grams/molar mass.
Using the coefficients in the balanced equation, convert mols N2 to moles NH3.
Convert moles NH3 to volume. moles x 22.4 L/mol = ??