The area of a rectangle is 60 in ^2. The length is 4 inches greater than the width. Find the length.

a) 6 in.
b) 3 in.
c) 4 in.
d) 10 in.

D

length=10 (width=6)
Multiply them: 10 x 6 = 60 in^2: check
4 inches greater than the width? check

Thank you Jen

You're welcome.

To find the length of the rectangle, we need to set up an equation using the given information.

Let's represent the width of the rectangle as "w". Since the length is 4 inches greater than the width, the length can be represented as "w + 4".

The formula for the area of a rectangle is Length * Width. In this case, the area is given as 60 square inches. So, we can set up the equation:

(w + 4) * w = 60

Now, let's solve this equation to find the value of "w" (the width) and then calculate the length.

Expanding the equation, we get:

w^2 + 4w = 60

Rearranging the equation to a quadratic form, we have:

w^2 + 4w - 60 = 0

Now, we can solve this quadratic equation by factoring, completing the square, or using the quadratic formula. In this case, let's factor the equation:

(w + 10)(w - 6) = 0

Setting each factor equal to zero and solving for "w", we have:

w + 10 = 0 or w - 6 = 0

Solving these equations, we get:

w = -10 or w = 6

Since the width cannot be negative, we discard the solution w = -10.

Therefore, the width of the rectangle is 6 inches. Since the length is 4 inches greater than the width, the length is:

w + 4 = 6 + 4 = 10 inches

The correct answer is d) 10 in.