Alg2
posted by Cal .
A piece of wood discovered in an archaeological dig was found to have lost 62% of it's carbon14. Carbon14 has a halflife of 5630 years. Determine it's age.

I would use the equation
amount = initialvalue(1/2)^(t/halflife)
so
.62 = 1(1/2)^(t/5630)
ln .62 = (t/5630)ln .5
t/5630 = ln .62/ln .5 = .689659879
t = 3882.785
The age is appr. 3883 years