How many moles of ammonium ions are in 0.807 g of ammonium carbonate?
moles (NH4)2CO3 = grams/molar mass.
moles NH4 will be twice moles (NH4)2CO3.
To determine the number of moles of ammonium ions in a given amount of ammonium carbonate, we need to use the concept of molar mass and stoichiometry.
Step 1: Determine the formula of ammonium carbonate: NH4CO3.
Step 2: Calculate the molar mass of ammonium carbonate by summing up the atomic masses of its constituent elements:
(1 × atomic mass of N) + (4 × atomic mass of H) + (1 × atomic mass of C) + (3 × atomic mass of O)
Step 3: Convert the given mass of ammonium carbonate to moles by dividing the mass by the molar mass.
Let's break down each step:
Step 1: The formula of ammonium carbonate is NH4CO3.
Step 2: Calculate the molar mass of ammonium carbonate:
Atomic mass of N = 14.01 g/mol
Atomic mass of H = 1.01 g/mol
Atomic mass of C = 12.01 g/mol
Atomic mass of O = 16.00 g/mol
Molar mass of NH4CO3 = (1 × 14.01) + (4 × 1.01) + (1 × 12.01) + (3 × 16.00) = 80.04 g/mol
Step 3: Convert the mass of ammonium carbonate to moles:
Given mass = 0.807 g
Number of moles = given mass / molar mass
Number of moles = 0.807 g / 80.04 g/mol
Calculating this division, we find that the number of moles of ammonium carbonate is approximately 0.01008 mol.
Since there is one ammonium ion (NH4+) per molecule of ammonium carbonate, the number of moles of ammonium ions is the same as the number of moles of ammonium carbonate.
Therefore, there are approximately 0.01008 moles of ammonium ions in 0.807 g of ammonium carbonate.