Calculus (repost)
posted by Katy .
Use implicit differentiation to find dy/dx if cos xy = 2x^2  3y.
I'm stuck on this problem because I'm getting thrown off on how to factor this. Here's my work so far:
{[(dy/dx)y + y]sin xy} = 4x  3(dy/dx)
{[(dy/dx)y + y]sinxy} + 3(dy/dx) = 4x
...now what?
Thx
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