How many grams of glacial acetic acid should be used to make 250 mL of 2.00 M acetic acid? Show all your work.

To determine how many grams of glacial acetic acid should be used to make 250 mL of 2.00 M acetic acid, we need to use the formula:

moles = concentration (mol/L) x volume (L)

First, let's convert the volume from milliliters (mL) to liters (L):

250 mL = 250/1000 = 0.25 L

Now, let's calculate the number of moles of acetic acid using the given concentration and volume:

moles = 2.00 M x 0.25 L = 0.5 moles

The molar mass of glacial acetic acid (CH3COOH) is approximately 60.05 g/mol. To determine the mass of acetic acid needed, we can use the formula:

mass = moles x molar mass

mass = 0.5 moles x 60.05 g/mol = 30.025 grams

Therefore, we would need approximately 30.025 grams of glacial acetic acid to make 250 mL of 2.00 M acetic acid.