How many molecules of hydrogen are produced if 13.05 g of Zn reacts with excess hydrochloric acid equation Zn plus HCL equals ZnCl2 plus H2?
This is a stoichiometry problem. First you have to balance your reaction:
Zn + 2HCL = H2 + ZnCl2
(This is irrelevant to answering the question because Zn and H2 both have coefficients of 1, but it's good to know)
So you're given 13.05g of Zinc, you have to convert that to moles first in order to find moles of hydrogen, then molecules of hydrogen.
13.05g Zn * 1molZn/65g = .201mols Zn
To convert mols Zn to mols H, use the ratio 1 mol H2 to 1 mol...so you have .201 mols of H2
Now that you've got .201 mols of H2, you can find the molecules of H2. Use Avogadro's Number:
.201mols H2 * 6.02x10^23molecules/1mol
...and there's your answer!
thanks!
To find the number of molecules of hydrogen produced, we need to follow these steps:
Step 1: Calculate the molar mass of Zn (Zinc)
The molar mass of Zn is 65.38 g/mol.
Step 2: Convert the given mass of Zn (13.05 g) to moles.
Number of moles = Mass / Molar mass
Number of moles of Zn = 13.05 g / 65.38 g/mol
Number of moles of Zn = 0.1995 mol
Step 3: Determine the stoichiometry of the reaction.
From the balanced equation, we can see that:
1 mole of Zn reacts to produce 1 mole of H2.
Step 4: Calculate the number of moles of H2 produced.
Number of moles of H2 = Number of moles of Zn
Thus, the number of moles of H2 produced is also 0.1995 mol.
Step 5: Calculate the number of molecules of H2.
Number of molecules = Number of moles * Avogadro's number
Number of molecules of H2 = 0.1995 mol * 6.022 × 10^23 mol^-1
Number of molecules of H2 = 1.199 × 10^23 molecules
Therefore, approximately 1.199 × 10^23 molecules of hydrogen (H2) are produced.
To determine the number of molecules of hydrogen produced in the given reaction, we need to follow these steps:
1. Write and balance the equation: The balanced equation for the reaction between zinc (Zn) and hydrochloric acid (HCl) is:
Zn + 2HCl → ZnCl2 + H2
2. Convert grams to moles: Convert the given mass of zinc (13.05 g) to moles by using the molar mass of zinc (65.38 g/mol):
moles of Zn = mass of Zn / molar mass of Zn
= 13.05 g / 65.38 g/mol
≈ 0.1991 mol
3. Determine the stoichiometry: From the balanced equation, we can see that the molar ratio between zinc (Zn) and hydrogen gas (H2) is 1:1. Therefore, the moles of hydrogen gas produced will also be approximately 0.1991 mol.
4. Convert moles to molecules: The Avogadro's number (6.022 × 10^23) represents the number of particles (atoms, molecules) in one mole. We can use this value to convert the moles of hydrogen gas to molecules:
molecules of H2 = moles of H2 x Avogadro's number
= 0.1991 mol x 6.022 × 10^23 molecules/mol
≈ 1.197 × 10^23 molecules
Therefore, approximately 1.197 × 10^23 molecules of hydrogen gas are produced when 13.05 g of zinc reacts with excess hydrochloric acid.