I have got differential pressure from an inclined manometer to be 2.8kPa and density of the fluid is 784kg/m^3. I need to calculate the manometer datum height. how do i do tht?? i already did it using formula pressure=density*g*h but i want ans to be 0.165 meters which i dnt get thnx for the help in advance.

To calculate the manometer datum height, you need to use the formula you mentioned: pressure = density * g * h.

Let's break down the formula:

- pressure is the differential pressure measured by the inclined manometer, which is given as 2.8 kPa.
- density is the density of the fluid inside the manometer, which is given as 784 kg/m^3.
- g is the acceleration due to gravity, which is approximately 9.8 m/s^2.
- h is the manometer datum height, the value we need to calculate.

Now, let's plug in the values into the formula:

2.8 kPa = 784 kg/m^3 * 9.8 m/s^2 * h.

To convert kPa to Pa, multiply the pressure by 1000:

2.8 kPa * 1000 = 784 kg/m^3 * 9.8 m/s^2 * h.

2800 Pa = 784 kg/m^3 * 9.8 m/s^2 * h.

Now, isolate h by dividing both sides of the equation by (784 kg/m^3 * 9.8 m/s^2):

h = 2800 Pa / (784 kg/m^3 * 9.8 m/s^2).

Calculating this:

h = 0.357 meters.

Therefore, the calculated manometer datum height is 0.357 meters, which is different from the desired value of 0.165 meters.

To achieve a manometer datum height of 0.165 meters, it seems there may be an error in the density, gravity, or pressure values or units. Please check your data and calculation steps to identify any errors that may have led to the incorrect result.