square roots of x+2=3
-9(x-3)^2=-7
I need help please
To find the square roots of a given equation, you need to isolate the variable on one side of the equation. Let's solve each equation step by step:
1. To find the square roots of x+2=3:
a. Start by subtracting 2 from both sides of the equation: x + 2 - 2 = 3 - 2.
This simplifies to x = 1.
b. Take the square root of both sides of the equation: √(x) = √(1).
The square root of 1 is 1, so x = 1.
Therefore, the solution to the equation x+2=3 is x = 1.
2. To solve -9(x-3)² = -7:
a. Start by dividing both sides of the equation by -9 to isolate the squared term:
-9(x-3)² / -9 = -7 / -9.
This simplifies to (x-3)² = 7/9.
b. Take the square root of both sides of the equation: √((x-3)²) = √(7/9).
Remember to consider both positive and negative square roots: x - 3 = ±√(7/9).
c. Solve for x by adding 3 to both sides of the equation:
x - 3 + 3 = ±√(7/9) + 3.
This simplifies to x = 3 ± √(7/9).
Therefore, the solution to the equation -9(x-3)² = -7 is x = 3 ± √(7/9).
If you need further clarification or have more questions, feel free to ask!