A car with a mass of 1435 kg moves at 11 m/s. What braking force is needed to bring the car to a halt in 10 s?
The impulse delivered, (force)*(time), must equal the initial monetum, (mass)*(velocity).
Thus F = M V/T , in Newtons
2500
the answer is clearly in the formula and if you just plug in it will give you the answer but you might just have to figure out one variable with another equation then plug back in, its simple not too hard...
To calculate the braking force needed to bring the car to a halt, we can use Newton's second law of motion, which states that the force acting on an object is equal to its mass multiplied by its acceleration:
F = m * a
In this case, we know the mass of the car is 1435 kg and it needs to be brought to a complete halt, so the final velocity is 0 m/s. The initial velocity is given as 11 m/s, and the time taken to stop is 10 s.
To find the acceleration, we can use the equation:
a = (v - u) / t
where:
v is the final velocity (0 m/s)
u is the initial velocity (11 m/s)
t is the time taken to stop (10 s)
Let's calculate the acceleration first:
a = (0 - 11) / 10
a = -11 / 10
a = -1.1 m/s^2
Note that the negative sign indicates that the acceleration is in the opposite direction of the car's initial motion.
Now we can calculate the braking force:
F = m * a
F = 1435 kg * -1.1 m/s^2
F = -1578.5 N
The negative sign in the answer indicates that the braking force is acting in the opposite direction of the car's initial motion. Therefore, the magnitude of the braking force needed to bring the car to a halt in 10 seconds is 1578.5 Newtons.