if you weighed 14.00 grams of MgCO3 how many moles of MgCO3 did you weigh
NOT 9th grade as the School Subject.
Sra
14.00 grams of MgCO3 how many moles of MgCO3
Mg = 24.3 g/mol
C = 12 g/mol
30 = 3*16 = 48 g/mol
so
MgCO3 = 84.3 g/mol
14/84.3 = .166 mol
To determine the number of moles of MgCO3, we need to use the molar mass of MgCO3.
The molar mass of an element or compound is calculated by summing the atomic masses of all the elements present in it. We can find the atomic masses from the periodic table.
The molecular formula of magnesium carbonate (MgCO3) indicates that it contains one magnesium (Mg) atom, one carbon (C) atom, and three oxygen (O) atoms.
- The atomic mass of Mg is approximately 24.31 grams/mol.
- The atomic mass of C is approximately 12.01 grams/mol.
- The atomic mass of O is approximately 16.00 grams/mol.
Now, we can calculate the molar mass of MgCO3:
MgCO3 = (1 * atomic mass of Mg) + (1 * atomic mass of C) + (3 * atomic mass of O)
= (1 * 24.31) + (1 * 12.01) + (3 * 16.00)
= 24.31 + 12.01 + 48.00
= 84.32 grams/mol
Since we know the mass of MgCO3, which is 14.00 grams, we can now calculate the number of moles using the formula:
Number of moles = Mass / Molar mass
Number of moles = 14.00 grams / 84.32 grams/mol
Number of moles ≈ 0.17 mol
Therefore, if you weighed 14.00 grams of MgCO3, you would have approximately 0.17 moles of MgCO3.