Is Glucose soluble in HCl, NaOH and NaHCO3 because it's soluble in water?
- I put soluble for all because it dissolves in water.
Is p-toluidine soluble in HCl, NaOH, and NaHCO3?
I put soluble in HCl, insoluble in NaOH and insoluble in NaHCO3.
Is benzoic acid soluble in HCl, NaOH, and NaHCO3?
- I got insoluble in HCl, soluble in NaOH and soluble in NaHCO3.
Is 2-naphthol soluble in HCl, NaOH, and NaHCO3?
- I got insoluble in all.
Is sodium sulphate soluble in HCl, NaOH, NaHCO3?
- I got soluble for all because it dissolves in water.
2-NAPHTHOL
Oh, chemistry! Let's dive in and find some humor in these solubility questions:
Is glucose soluble in HCl, NaOH, and NaHCO3 because it's soluble in water?
Glucose just loves to be the "solu-star" and dissolve in water! It's like a fish in water, swimming happily. But when it comes to HCl, NaOH, and NaHCO3, glucose decides to take a break from its solubility adventures and stays puzzled by these chemicals. So, in other words, glucose is saying, "Sorry, acids and bases, I'm just gonna hang out with water for now!"
Is p-toluidine soluble in HCl, NaOH, and NaHCO3?
Ah, p-toluidine, the mysterious solubility traveler! When it meets HCl, it decides to have a party and dissolve, feeling all "solu-fantastic." But when it sees NaOH and NaHCO3, p-toluidine goes into hiding. It's like a magician who disappears when you try to dissolve it in those chemicals. So p-toluidine whispers, "Yes to HCl, no to NaOH and NaHCO3 – I'm a solubility illusionist!"
Is benzoic acid soluble in HCl, NaOH, and NaHCO3?
Benzoic acid is a total solubility chameleon, showing different tricks for different chemicals! When faced with HCl, it's like, "Hmm, nah, not gonna dissolve." But when NaOH comes along, benzoic acid does a double-take and says, "Oh hey, NaOH! Let's be BFFs and dissolve together!" And even NaHCO3 gets the same treatment – benzoic acid says, "You, too, NaHCO3, let's have a solubility party!" So, yes to NaOH and NaHCO3, but no to HCl. Benzoic acid is quite the solubility socialite!
Is 2-naphthol soluble in HCl, NaOH, and NaHCO3?
Ah, 2-naphthol, the solubility rebel! It refuses to dissolve in any of those chemicals – HCl, NaOH, and NaHCO3. It's like a mischievous kid who jumps out of the way when you try to catch them. So, 2-naphthol says, "Sorry, not gonna dissolve in your acid, bases, or bicarbonates – I'm a solubility troublemaker!"
Is sodium sulfate soluble in HCl, NaOH, and NaHCO3?
Oh, sodium sulfate, the "solu-champ" of the group! It's like a superhero of solubility, saying, "I'll dissolve in anything, anywhere!" HCl, NaOH, NaHCO3 – sodium sulfate is not afraid of any of them. It jumps right into the water and says, "Hey, chemicals, watch me dissolve in these solutions like it's no big deal!" So, bravo to sodium sulfate for being soluble in all of them. It's the solubility hero we all need!
Remember, these answers are all in good fun! Always make sure to check the actual solubility of chemicals for accurate information.
Glucose is indeed soluble in water, which means it will also dissolve in HCl, NaOH, and NaHCO3. So, you are correct in stating that glucose is soluble in all three solutions.
For p-toluidine, it is soluble in HCl, which means it will dissolve in that solution. However, it is insoluble in NaOH and NaHCO3, meaning it will not dissolve in those solutions. Therefore, your answer of soluble in HCl and insoluble in NaOH and NaHCO3 is correct.
Benzoic acid, on the other hand, is insoluble in HCl. However, it is soluble in NaOH and NaHCO3, so it will dissolve in those solutions. Therefore, your answer of insoluble in HCl and soluble in NaOH and NaHCO3 is correct for benzoic acid.
For 2-naphthol, it is insoluble in all three solutions. Therefore, your answer of insoluble in HCl, NaOH, and NaHCO3 is correct.
Regarding sodium sulphate, it is indeed soluble in water. Therefore, it will also be soluble in HCl, NaOH, and NaHCO3, as those solutions are composed of water. So, your answer of soluble for all is correct.
To determine the solubility of a compound in different solvents such as HCl, NaOH, and NaHCO3, we need to consider the chemical properties of the compound and how it interacts with each solvent.
In general, the solubility of a compound can be affected by factors such as polarity, acid-base properties, and the presence of functional groups. Let's go through each compound to understand their solubility properties in different solvents:
1. Glucose:
As you correctly mentioned, glucose is soluble in water. Since HCl, NaOH, and NaHCO3 are all water-based solutions, it is safe to assume that glucose will be soluble in all of them.
2. p-toluidine:
p-toluidine is a basic compound. It can form ionic salts with acids, hence it is expected to be soluble in HCl. On the other hand, NaOH and NaHCO3 are basic solutions, so p-toluidine is expected to be insoluble in them. Therefore, your answer was correct.
3. Benzoic acid:
Benzoic acid is a weak acid with a carboxylic acid functional group. It can form salts with bases. Hence, benzoic acid dissolves in NaOH and NaHCO3, as they are basic solutions. However, it does not dissolve in HCl, as it would rather react to form the benzoate ion. Therefore, your answer was correct.
4. 2-naphthol:
2-naphthol is a slightly polar compound and not very soluble in water. It does not react strongly with acids or bases. Therefore, it is expected to be insoluble in HCl, NaOH, and NaHCO3. Your answer was correct.
5. Sodium sulfate:
Sodium sulfate is an ionic compound consisting of Na+ and SO4 2- ions. Being an ionic compound, it is highly soluble in water. Since HCl, NaOH, and NaHCO3 are all water-based solutions, sodium sulfate is expected to be soluble in all of them. Your answer was correct.
To summarize:
- Glucose is soluble in HCl, NaOH, and NaHCO3.
- p-toluidine is soluble in HCl and insoluble in NaOH and NaHCO3.
- Benzoic acid is insoluble in HCl and soluble in NaOH and NaHCO3.
- 2-naphthol is insoluble in HCl, NaOH, and NaHCO3.
- Sodium sulfate is soluble in HCl, NaOH, and NaHCO3.
Remember to always consider the chemical properties of the compounds and their compatibility with the solvents when determining solubility.