consecutive even integers can be represented by x,x+2,x+4 and so on. write an equation and solve to find 3 consecutive even integers whose sum is 54.
is this how
x+x+2+x+4=54
x= 16
Right! :-)
Do this problem the same way I showed you for the similar problem.
To find three consecutive even integers whose sum is 54, we can represent the integers as x, x + 2, and x + 4.
Now, we can set up an equation to solve for x:
x + (x + 2) + (x + 4) = 54
Simplifying the equation:
3x + 6 = 54
Next, we can subtract 6 from both sides of the equation:
3x = 54 - 6
3x = 48
To isolate x, we divide both sides of the equation by 3:
x = 48 / 3
x = 16
So, the first even integer is 16.
To find the other two consecutive even integers, we substitute the value of x back into the equation:
x + 2 = 16 + 2 = 18
x + 4 = 16 + 4 = 20
Therefore, the three consecutive even integers whose sum is 54 are 16, 18, and 20.