Write an equation of the line satisfyingg the given conditions.
Slope = -2/3; y-intercept of 2
y = mx + c is a line with slope=m and a y-intercept of c. And hence the reqd. line: y= -2x/3 + 2 or 2x+3y=6
Ajit
56times23=(56times20)+(56times n)
To write an equation of a line given the slope and y-intercept, you can use the slope-intercept form of a linear equation: y = mx + b.
In this case, the slope (m) is -2/3 and the y-intercept (b) is 2. Plug these values into the equation:
y = (-2/3)x + 2.
Therefore, the equation of the line that satisfies the given conditions is y = (-2/3)x + 2.