# Algebra

posted by .

Use the discriminant to determine how many real number solutions the equation has.

t^2 + 8t + 16 = 0

• Algebra -

discriminant= b2-4ac
(8)^2-4(1)(16)
64-64=0
One real root (because it equals 0).
If it was a positive number, there would be two real roots. If it was a negative number, there would be two COMPLEX roots.

## Similar Questions

1. ### Algebra

Consider the equation: 4x^2 – 16x + 25 = 0 (a) Show how to compute the discriminant, b^2 – 4ac, and then state whether there is one real-number solution, two different real-number solutions, or two different imaginary-number solutions. …
2. ### math

Use the discriminant to determine how many real-number solutions the equation has. v^2 - 7v + 5 = 0
3. ### math

Use the discriminant to determine how many real-number solutions the equation has. v2 - 7v + 5 = 0
4. ### algebra

Use the discriminant to determine how many real-number solutions the equation has. s2 - 5s + 6 = 0
5. ### Algebra HELP:(

Use the discriminant to determine how many real-number solutions the equation has. 36x2 - 12x + 1 = 0 How do I do this?
6. ### Discriminant

Use the discriminant to determine how many real-number solutions the equation has 1 - 7a2 = -7a - 2 A) 2 B) 1 C) 0 Not sure how to work this problem
7. ### Math

Use the discriminant to determine how many real number solutions the equation has 1-7a^2=-7a-2
8. ### intermediate algebra

3x^2+9x+4=0 the discriminant is 33, using the discriminant to determine the number of real solutions
9. ### Algebra II

1)What method(s) would you choose to solve the equation: x2 + 2x - 6 = 0 A. Square roots; there is no x-term. B. Quadratic formula, graphing; the equation cannot be factored easily since the numbers are large. C. Factoring; the equation …
10. ### Algebra

Determine the discriminant for the quadratic equation -3 = x^2 + 4x + 1. Based on the discriminant value, how many real number solution does the equation have?

More Similar Questions