calculus
posted by alex .
Now we prove Machin's formula using the tangent addition formula:
tan(A+B)= tanA+tanB/1tanAtanB.
If A= arctan(120/119) and B= arctan(1/239), how do you show that
arctan(120/119)arctan(1/239)=arctan1?
Respond to this Question
Similar Questions

Calculus
Note that pi lim arctan(x ) =  x > +oo 2 Now evaluate / pi \ lim arctan(x )   x x > +oo \ 2 / I'm not exactly sure how to attempt it. I have tried h'opital's rule but I don't believe you can use it here. Any help … 
calculus
Let f be a function defined by f(x)= arctan x/2 + arctan x. the value of f'(0) is? 
calc
also: integral of tan^(1)y dy how is integration of parts used in that? 
Math
Arrange these in order from least to greatest: arctan(sqrt3), arctan 0, arctan(1/2) So far I got the first two values, arctan(sqrt3), and that's 150 degrees. Arctan 0 would be zero degrees. I'll use just one answer for now, but I … 
calculus
h(x)= integral from (1, 1/x) arctan(2t)dt part 1: let U= 1/x and du= ? 
calculus
h(x)= integral from (1, 1/x) arctan(2t)dt part 1: let U= 1/x and du= ? 
PRECALC
sin(arctan(4/3) okay so i made arctan(4/3) = x so im solving for sin(x) and x= arctan(4/3) so then tanx = 4/3 and now im stuck i don't know what to do after that 
precal
The values of x that are solutions to the equation cos^(2)x=sin2x in the interval [0, pi] are a. arctan(1/2) only b. arctan(1/2) and pi c. arctan(1/2) and 0 d. arctan(1/2) and (pi/2) e. arctan(1/2), o, and (pi/2) 
check my arctan please
arctan(1/12)= 4.763 rounded to the nearest tenth degree, which is 4.8? 
Algebra 2
In triangle ABC , <C is a right angle. Find the remaining sides and angles. Round your answers to the nearest tenth. Show your work. a = 3, c = 19 c^2= a^2+b^2 19^2 = 3^2+b^2 361= 9+b^2 b= √352 = 18.8 tanA= 3/18.8 A= arctan …