A particle accelerated by a potential difference enters a velocity selector. The particle travels staright when the magnetic field is 0.400 T and the electric field is 6.30 x 10^5 V/m. Once the electric field is turned off, a sensor determines that the radius or the particle's path is 4.11 cm.
What is the charge to mass ratio of this particle?
This is what i understand..
1) first find the velocity
using formula v =E/B
2) then use q/m = v / B x r
am I right??
q V B = m V^2/r, so
q/m = V/(B*r)
Yes to both questions
thank you =)
Is this particle an electron, proton, alpha particle or non of the above.
Yes, you are on the right track! To find the charge to mass ratio of the particle, you need to follow these steps:
1) Find the velocity (v): Since the particle travels straight in the velocity selector, the electric force (Fe) and magnetic force (Fm) must be equal and opposite, resulting in no net force acting on the particle. We can equate these forces:
Fe = Fm
qE = qvB
E = vB
v = E/B
2) Calculate the charge to mass ratio (q/m): Now that you have the velocity (v) of the particle, you can substitute it into the equation:
q/m = v / (B * r)
where B is the magnetic field and r is the radius of the particle's path.
Remember to convert the given values to SI units before plugging in the values into the equation.