# Algebra II

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Growth and Decay

Dave bought a new car 8 years ago for \$8400. Tobuy a new car comparably equipped now would cost \$12,500. Assuming a steady rate of increase, what was the yearly rate of inflation in car prices over the 8-year period?

Is there an equation and could someone post the answer and (if someone could post the steps)?

• Algebra II -

8400 + 8x = 12500
8x = 4100
x = \$512.50 (amount of inflation per year)

Note that you cannot convert this to percent rate because it wouldn't be steady. For the first year, 512.5/8400 = 6.1%. For the second year, the car is going to cost 8912.5, and 512.5/8912.5 = 5.75%. And so on...

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