Factor completely
3p^2q + 9p^2q^2 - 12p^2q^3
I have done the following:
3p^2q(1+3q-4q^)
but then i get stuck..not sure if that's the final answer..
edit: should be 3p^2q(1+3q-4q^2)
I can't factor it any further.
To factor completely, we need to identify common factors among all the terms and factor them out.
In this case, we can factor out the common factor of 3p^2q from each term. Let's factor it out step by step:
First, factor out 3p^2q:
3p^2q(1 + 3q - 4q^3)
Now, let's focus on the expression inside the parentheses, which is 1 + 3q - 4q^3. We need to analyze if there are any common factors that can be factored out.
This expression does not appear to have any common factors other than 1. Therefore, we cannot factor it any further.
Therefore, the completely factored form of the original expression is:
3p^2q(1 + 3q - 4q^3)
So, your answer is correct!