Using calories, calculate how much heat 32.0g of water absorbs when it is heated from 25.0 degrees C to 80.0 degrees C. How many joules is this?

Are these steps right?

32.0g x 55*C = 1760 calories = 420.65 Joules

Using calories, calculate how much heat 32.0g of water absorbs when it is heated from 25.0 degrees C to 80.0 degrees C. How many joules is this?

To calculate the heat absorbed by the water, you need to use the specific heat capacity of water. The specific heat capacity of water is approximately 4.186 J/g°C.

Here are the correct steps:

1. Calculate the change in temperature:
ΔT = final temperature - initial temperature
ΔT = 80.0°C - 25.0°C
ΔT = 55.0°C

2. Calculate the heat absorbed by the water:
Q = mass of water × specific heat capacity × ΔT
Q = 32.0g × 4.186 J/g°C × 55.0°C
Q ≈ 7,315.52 Joules

Therefore, 32.0g of water absorbs approximately 7,315.52 Joules of heat when heated from 25.0°C to 80.0°C.

To calculate the heat absorbed by water when it is heated from one temperature to another, you need to use the formula:

Heat Absorbed = mass of water (in grams) x specific heat capacity of water (in calories/gram * degree Celsius) x change in temperature (in degrees Celsius).

Let's go through the steps again:

1. Calculate the change in temperature:
Change in temperature = final temperature - initial temperature
Change in temperature = 80.0°C - 25.0°C = 55.0°C

2. Calculate the heat absorbed (in calories):
Heat absorbed = mass of water x specific heat capacity x change in temperature
Heat absorbed = 32.0g x 1 calorie/gram°C x 55.0°C
Heat absorbed = 1760 calories

3. Convert calories to joules:
1 calorie = 4.184 joules
Heat absorbed in joules = 1760 calories x 4.184 joules/calorie
Heat absorbed in joules = 7353.44 joules (rounded to two decimal places)

So, the correct calculation is as follows:

Heat absorbed = 1760 calories = 7353.44 joules (rounded to two decimal places).

Technically, no. Realistically, #1 is ok but not #2.

The technical part is that you didn't show the calorie as 1 cal/g*c but
32 x 1 x 55 = 1760 calories.

But you DIVIDED by 4.184 for #2, you should have multiplied by 4.184.
mass x specific heat x delta T.