A snail climbs a wall that is 16 feet high. Each day the snail climbs 5 feet, but each night it slips back down 3 feet. How many days will it take for the snail to get to the top of the wall
it will take 8 days for the snail to reach the top.
5-3+5-3+5-3+5-3+5-3+5-3+5-3+5-3= 16
Day 1: 0+5=5
Night 1: 5-3=2
Day 2: 2+5=7
Night 2: 7-3=4
Day 3: 4+5=9
Night 3: 9-3=6
Day 4: 6+5=11
Night 4: 11-3=8
Day 5: 8+5=13
Night 5: 13-3=10
Day 6: 10+5=15
Night 6: 15-3=12
Day 7: 12+5=17
The snail is now out of the well.
To figure out how many days it will take for the snail to reach the top of the wall, we can break down the snail's progress each day and night.
Each day, the snail climbs 5 feet. Each night, it slips back down 3 feet.
So the net progress the snail makes each day is 5 - 3 = 2 feet.
The snail needs to climb a 16-foot wall, so we can divide 16 by the net progress the snail makes each day:
16 feet / 2 feet per day = 8 days.
Therefore, it will take the snail 8 days to reach the top of the wall.